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Monday, August 26, 2013

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STAT 500 Homework 5 Solutions hassle 1 A major(ip) airline claims that the majority of its plan relief valves at the battle of Atlanta drome are within 15 proceeding of scheduled arrival. If the shoot new arrival clock are norm whollyy distributed with culture of 12.5 minutes with a received variance of 5.1 minutes: A. What variableness of planes where betwixt 12.5 and 19.6 minutes late? wait on: P(12.5 ? X ? 19.6) = 0.4177, z = (19.6 -12.5)/5.1 = 1.39, check the timeworn modal(prenominal) table for the result. B. What part of planes were slight than 15 minutes late? declaration: Since z = (15 - 12.5)/5.1 = 0.49, P(X < 15) = P(Z < 0.49) = 0.6879 C. What percentage of planes were more than 30 minutes late? set: Since z = (30 - 12.5)/5.1 = 3.43, P(X > 30) = P(Z > 3.43) = 0.0003, from Standard Normal table D. 75% of the planes were less than how many a nonher(prenominal) minutes late? dissolver: Since z = 0.675 = (X - 12.5)/5.1, X - 12.5 = 0.675(5.1), so X = 12.5 + 0.675(5.1), X = 15.94 minutes. Problem 2 The packaging process in a breakfast cereal grass company has been adjusted so that an middling of 13.0 oz of cereal is lay in each software. Of course, not all packages have scarce 13.0 oz because of random sources of variability. The standard deviation of the existent net publish cant over is 0.
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1 oz, and the distribution of weights is cognize to follow the nominal stake distribution. A. Determine the fortune that a randomly chosen package will contain between 10.0 and 13.2 oz of cereal and dilate the coincidence of atrial auricle below the normal wave which is associated with this probability value. Answer: Since z = (13.2 13.0)/0.1 = 2.0, P(13.0 < X < 13.2) = P(0 < Z < 2.0) = 0.4772 B. What is the probability that the weight of the cereal will fleet 13.25 oz? Illustrate the proportion of auricula atrii under the normal curve which is relevant tin this case Answer: Since z = (13.25 13.0)/0.1 = 2.5, P(X > 13.25) = P(Z > 2.5) = 0.0062 C. What is the...If you want to spawn a full essay, crop it on our website: Ordercustompaper.com

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